![]() ![]() † † margin: y y x - 2 - 1 1 2 - 2 - 1 1 2 50 water line not to scale d ( y ) = 50 - y Figure 6.5.8: Measuring the fluid force on an underwater porthole in Example 6.5.4. The truth is that it is not, hence the survival tips mentioned at the beginning of this section. ![]() This is counter-intuitive as most assume that the door would be relatively easy to open. Most adults would find it very difficult to apply over 500 lb of force to a car door while seated inside, making the door effectively impossible to open. Find the fluid force on the vertical side of the tank, where the dimensions are given in feet. = ∫ - 2.25 0 62.4 ( - y ) 10 / 3 d y Calculate the fluid force on one side of a semi-circular plate of radius 5 ft that rests vertically on its diameter at the bottom of a pool filled with water to a depth of 6 ft. Using the weight-density of water of 62.4 lb/ft 3, we have the total force as We adopt the convention that the top of the door is at the surface of the water, both of which are at y = 0. Since the curved surface of the gate is part of a cylinder, the water exerts no. Its length is 10 / 3 ft and its height is 2.25 ft. is equal in magnitude to the force F on the fluid at the vertical plane. SolutionThe car door, as a rectangle, is drawn in Figure 6.5.7. ![]()
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